Figure 1 above is made up of two parallel ducted fans, propellers, operated with electrical input. Both have the same thrust and when operate, they draw air from the front to the back. When they operate they cause lower pressure at the front and higher pressure at the back like Higher Pressures 1 and 2.

Both fans convert electrical input to mechanical output in spinning form. When both fans spin in air or water, they cause two forms of outputs at the front and back. At the front, they create a Lower Pressure as an output and at the back they create a Higher Pressure as another output. The output, at the back, propels both fans forward.

Figure 2 above is the same like figure 1 except both ducts, pipes, separated and link at the front to a common pipe, which is closed at the back. Now when both propellers operate a third higher pressure, higher pressure 3, is generated between both pipes at HP point. This third higher pressure is a natural atmospheric pressure, which is higher than the lower atmospheric pressure at LP point inside at the back of common pipe. This is because both propellers draw air from this point. This causes atmospheric pressure at LP point to fall. So the fall of atmospheric pressure at LP point acts as input to the higher atmospheric pressure at HP point. The fall of atmospheric pressure at LP is the same output of figure 1 at the front.

Figure 3 above is the same like figure 2 above with more details. Hydro-Atmospheric Machine is the barrier between LP and HP points. This barrier is the back of common pipe. It doesn't have any moving parts, which means it is 100% efficient. This implies that the output, higher pressure 3, at HP point is exactly equal to the lower pressure hydraulic or atmospheric input at LP.

The electric machines have moving parts, which have weight and cause friction. The electrical input converted to output inside the electrical machines. Some of the output used inside machines to overcome friction and weight of components and some output lost as heat. So the output of these electrical machines is always a lot less than the input.

Total value of Higher Pressure 3 at HP point, figures 2 and 3, depends on the area between LP and HP points. This area is equal to the area of air passages of both electric fans, propellers, in figures 2 and 3. Air passage areas of a fan is made up of areas between each two blades. If air passage area of each fan of figures 2 and 3 is 500.00 Sq centimetre the area between LP and HP will become 1000.00 sq centimetre. This gives higher pressure 3 a potential of 1000.00kg without input cost. The use of lower pressure at the front as input at LP doesn't change output values, generated by external input, at the front and back as explained in figure 1.

Figure 4 above is a ducted fan. When it doesn't operate, atmospheric pressure is the same at front and back. It is in an equilibrium state.

In figure 5 above, the fan is getting an external input and operating. It draws air from the front to the back. This causes lower pressure at the front and higher pressure at the back. In other words, the fan generates two forms of outputs, one at the front as Lower Pressure Output and one at the back as Higher Pressure Output.

Now the question is this: does the fan use the External Input to generate both outputs? To answer this question, we need to know how the fan causes lower pressure at the front and higher pressure at the back. When the fan starts operating, it throws or pumps out air between its blades back ward. This causes lower atmospheric pressure between the blades. External higher atmospheric pressure at the back and front, as in figure 6 above, rush to bring back atmospheric pressure between blades to equilibrium. But only at the front, external atmospheric pressure can push air between the blades, it can not do the same at the back because the fan operates against it, it pushes air backward against external atmospheric pressure and generates a pressure higher than external atmospheric pressure as in figure 6 above.

This means the fan has to work only to throw or pump out air between blades backward against external atmospheric pressure. But the fan doesn't do any work to pull air from the front. Under higher external atmospheric pressure at the front, air rushes to enter between blades because atmospheric pressure between blades is lower.

So the fan doesn't do any work at the front to pull air, which is done by external higher atmospheric pressure naturally. But the fan has to work to throw or pump out air between its blades backward and has to work against external atmospheric pressure at the back. Therefore the output at the front doesn't cost, use, any external input but the output at the back costs, uses, all the external input.

Usually the output at the front is not used and Hydro-Atmospheric side of HAAM uses this unused front output as input to generate a usable output. So the output of hydro-atmospheric side of HAAM is not something for nothing. Therefore, HAAM complies with the second law of thermodynamics.

In figure 7 above we have two inputs, one is electrical and the other is a lower pressure or LP. The electrical input operates both electrical machines, fans, to produce outputs HP1 and HP2. Both fans draw air from common pipe to create a lower pressure at the front and higher pressures 1 and 2 at the back. Lower pressure input, LP, operates hydro-atmospheric machine to produce output HP3 or higher pressure 3. HP3 output is an atmospheric pressure differentiation between HP3 and LP points. Atmospheric pressure at LP is lower because both fans draw air from this point, LP.

Lower Pressure, LP, has a thrust with a potential of 14.7 psi, pounds per square inch, or 1.00kg/square centimetre as muximum. Higher pressures 1 and 2 or HP1 and HP2 can go higher than 14.7 psi or 1.00kg/square centimetre. We can calibrate the system so that the thrusts HP1 and HP2 at the back don't exceed the thrust of LP at the front. If both don't exceed LP they will always equal to it as in the following formula 1:

1- HP1 + HP2 = LP Both sides equal but on opposite direction.

2- But LP = HP3 too, both sides equal but on opposite direction. Hydro-Atmospheric machine is nothing more than the barrier between LP and HP3. It doesn't have any moving parts. So it is 100% efficient.

3- Therefore HP1 + HP2 = HP3 Both sides equal but on the same direction.

Therefore the system has doubled the output without input cost. This has important implication because HAAM could become a self-sustaining and energy providing system. For example assume both fans in the figure has an output efficiency of 60%. Hydro-atmospheric side of HAAM doubles it to 120%. Use 100% to feed back the system and put the other 20% for any use. Theoretically this is possible.

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(c)Copyright 2012 The Inventor: R. M. Ahmad Email: swisaw@hotmail.co.uk